SceneNodeList

Represents the children of a scenenode. Typically accessed via the SceneNode.children property.

This is not an Array, so you must use at(i) instead of [i] to access children by index. It has a number of Array-like methods such as forEach for convenience, however. For best performance, iterate the list using these methods rather than repeatedly calling at().

Items in this list are ordered from lowest z order to highest.

Kind: class

Example

let node = ...;
console.log("Node has " + node.children.length + " children");
console.log("First child: " + node.children.at(0));  // do not use `[0]` - it will not work!
node.children.forEach(function (childNode, i) {
    ...
});

See: SceneNode.children

• SceneNodeList
  • .length : number
  • .forEach(callback, thisArg) ⇒ void
  • .forEachRight(callback, thisArg) ⇒ void
  • .filter(callback, thisArg) ⇒ Array.<!SceneNode>
  • .map(callback, thisArg) ⇒ Array.<*>
  • .some(callback, thisArg) ⇒ boolean
  • .at() ⇒ SceneNode

sceneNodeList.length : number

Number of children in the list.

Kind: instance property of SceneNodeList
Read only: true

sceneNodeList.forEach(callback, thisArg) ⇒ void

Iterate all children in the list.

Kind: instance method of SceneNodeList

sceneNodeList.forEachRight(callback, thisArg) ⇒ void

Iterate all children in the list, in reverse order (highest z order to lowest).

Kind: instance method of SceneNodeList

sceneNodeList.filter(callback, thisArg) ⇒ Array.<!SceneNode>

Iterates all children and returns an array of just the children that passed the filter function's test.

Kind: instance method of SceneNodeList

sceneNodeList.map(callback, thisArg) ⇒ Array.<*>

Iterates all children and returns an array of the map function's result value for each child node.

Kind: instance method of SceneNodeList

sceneNodeList.some(callback, thisArg) ⇒ boolean

Iterates children until the test returns true for at least one child.

Kind: instance method of SceneNodeList
Returns: boolean - True if the test function returned true for at least one child.

sceneNodeList.at() ⇒ SceneNode

Note: calling at() repeatedly (e.g. in a for loop) is not as fast as using SceneNodeList's iteration methods such as forEach(), some(), or map().

Kind: instance method of SceneNodeList
Returns: ?SceneNode - Child node at the specified index in the list, or null if index is out of bounds.